Parachute Drop
Jump out of a plane! Choose how you fall, when to open your parachute and how big it is, then watch your speed on the graph.
- Height
- 3000 m
- Speed
- 0.0 m/s
- Time
- 0.0 s
- Terminal velocity
- 55.2 m/s
- Air resistance
- 0 N
- Opening jolt
- 5.1 g
The maths, live
Weight W = m × gW = 80 × 9.81 = 785 NAir resistance F = ½ × ρ × Cd·A × v²F = ½ × 1.2 × 0.43 × 0.0² = 0 NTerminal velocity (F = W) v = √(2mg ÷ ρCd·A)v = √(2 × 80 × 9.81 ÷ (1.2 × 0.43)) = 55.2 m/sNet force F = W − air resistanceF = 785 − 0 = 785 NWatch the graph flatten out: when air resistance grows as big as your weight, you stop speeding up. That is terminal velocity.
How it works
As you fall faster, the air pushes back harder. Air resistance grows with the square of your speed: F = ½ × ρ × Cd·A × v². When it grows as big as your weight, the forces are balanced, you stop speeding up and fall at a steady speed called terminal velocity. A skydiver lying belly down reaches about 55 m/s (200 km/h).
Opening the parachute makes the area facing the air much bigger, so air resistance is suddenly much larger than your weight. The net force points upwards and you slow down, until air resistance matches your weight again at a new, gentle terminal velocity of about 5 m/s.
Try this
- Jump belly down, then head down. Which has the bigger terminal velocity?
- Try the small parachute. How fast do you land? What about the large one?
- Look at the graph just after the parachute opens. Why does the line drop so steeply?